x^2+4x-297=0

Solution for x^2+4x-297=0 equation:

x^2+4x-297=0

a = 1; b = 4; c = -297;
Δ = b2-4ac
Δ = 42-4·1·(-297)
Δ = 1204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1204}=\sqrt{4*301}=\sqrt{4}*\sqrt{301}=2\sqrt{301}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{301}}{2*1}=\frac{-4-2\sqrt{301}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{301}}{2*1}=\frac{-4+2\sqrt{301}}{2}
$